Engeneering Mathematics?

The series can be written as a sum (k�/k!)= sum(a(k)), k= 1 to infinity. The series converges if |a(k+1)/a(k)|< 1. Now |(k+1)�/(k+1)! * k!/k�|=|k�/(k+1)|. This term is always >1 for every k>=2 so the series diverges.